4x^(5/2)-20=0

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Solution for 4x^(5/2)-20=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

4*x^(5/2)-20 = 0

4*x^(5/2) = 20 // : 4

x^(5/2) = 5

x^(5/2) = 5 // ^ 2

x^5 = 25 // ^ 1/5

x = 25^(1/5)

x = 25^(1/5)

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